<rss version="2.0" xmlns:a10="http://www.w3.org/2005/Atom"><channel><title>Inflectra Customer Forums: Kronodesk DB structure (Thread)</title><description> Hi, I need to check for entries with duplicate names. Our helpdesk can execute a query for me, but they need to have the working query. In general I need something like this (but I do not have a way to know the DB tables and fields names)      SELECT [NameColumn], COUNT(*) AS dupeCount     FROM [Helpdek Tickets]     GROUP BY [NameColumn]     HAVING COUNT(*) &gt; 1    Can somebody help with the correct names? </description><language>en-US</language><copyright>(C) Copyright 2006-2026 Inflectra Corporation.</copyright><managingEditor>support@inflectra.com</managingEditor><category domain="http://www.dmoz.org">/Computers/Software/Project_Management/</category><category domain="http://www.dmoz.org">/Computers/Software/Quality_Assurance/</category><generator>KronoDesk</generator><a10:contributor><a10:email>support@inflectra.com</a10:email></a10:contributor><a10:id>http://www.inflectra.com/kronodesk/forums/threads</a10:id><ttl>120</ttl><link>/Support/Forum/kronodesk/issues-questions/1847.aspx</link><item><guid isPermaLink="false">threadId=1847</guid><author>Venelina Jordanova (vjordanova@delftdi.com)</author><category domain="http://www.inflectra.com/kronodesk/thread/tag">db structure</category><title>Kronodesk DB structure</title><description> Hi, I need to check for entries with duplicate names. Our helpdesk can execute a query for me, but they need to have the working query. In general I need something like this (but I do not have a way to know the DB tables and fields names)      SELECT [NameColumn], COUNT(*) AS dupeCount     FROM [Helpdek Tickets]     GROUP BY [NameColumn]     HAVING COUNT(*) &gt; 1    Can somebody help with the correct names? </description><pubDate>Mon, 07 May 2018 16:11:43 -0400</pubDate><a10:updated>2018-05-08T15:45:59-04:00</a10:updated><link>/Support/Forum/kronodesk/issues-questions/1847.aspx</link></item><item><guid isPermaLink="false">messageId=3276</guid><author>Jim R (donotreply5@kronodesk.net)</author><title> Hi  Please use something like:   SELECT NAME, COUNT(*) AS DupeCount
FROM KRN_TICKET
GROUP BY NAME
H</title><description> Hi  Please use something like:   SELECT NAME, COUNT(*) AS DupeCount
FROM KRN_TICKET
GROUP BY NAME
HAVING COUNT(*) &gt; 0   Regards  Jim </description><pubDate>Tue, 08 May 2018 13:43:34 -0400</pubDate><a10:updated>2018-05-08T13:43:34-04:00</a10:updated><link>/Support/Forum/kronodesk/issues-questions/1847.aspx#reply3276</link></item><item><guid isPermaLink="false">messageId=3277</guid><author>Venelina Jordanova (vjordanova@delftdi.com)</author><title> Thanks, Jim! </title><description> Thanks, Jim! </description><pubDate>Tue, 08 May 2018 15:45:59 -0400</pubDate><a10:updated>2018-05-08T15:45:59-04:00</a10:updated><link>/Support/Forum/kronodesk/issues-questions/1847.aspx#reply3277</link></item></channel></rss>